A body accelerates uniformly from rest at 2ms -... - WAEC Physics 1994 Question
A body accelerates uniformly from rest at \(2ms^{-2}\). Calculate the velocity after traveling 9m
A
36\(ms^{-1}\)
B
18\(ms^{-1}\)
C
6\(ms^{-1}\)
D
4.5\(ms^{-1}\)
correct option: c
(V^2= U^2+2as) =(0+ 2\times 2ms^{-2}\times 9 =36ms^{-1}) thus
V=(\sqrt{36m^2s^{-2}}) = (6ms^{-1})
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