A body accelerates uniformly from rest at 2ms -... - WAEC Physics 1994 Question
A body accelerates uniformly from rest at \(2ms^{-2}\). Calculate the velocity after traveling 9m
A
36\(ms^{-1}\)
B
18\(ms^{-1}\)
C
6\(ms^{-1}\)
D
4.5\(ms^{-1}\)
correct option: c
\(V^2= U^2+2as\) =\(0+ 2\times 2ms^{-2}\times 9 =36ms^{-1}\) thus
V=\(\sqrt{36m^2s^{-2}}\) = \(6ms^{-1}\)
V=\(\sqrt{36m^2s^{-2}}\) = \(6ms^{-1}\)
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